x^2+38x-168=0

Solution for x^2+38x-168=0 equation:

x^2+38x-168=0

a = 1; b = 38; c = -168;
Δ = b2-4ac
Δ = 382-4·1·(-168)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-46}{2*1}=\frac{-84}{2}
=-42
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+46}{2*1}=\frac{8}{2}
=4
$